Loads More Diagnostic Work arriving in January

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  • David Green
    Senior Member
    • Oct 2009
    • 382

    Loads More Diagnostic Work arriving in January

    New legislation arriving January will introduce more fault diagnostic work, the mot is to bring in ALL instrument display warning lamps like;

    SRS, Air Bag systems, Brake lights monitoring, tyre pressure monitoring, Traction Control lights etc.

    Hope the equipment is up to it ALL

    David
  • sbreland73
    Senior Member
    • Jan 2009
    • 1076

    #2
    Must be nice, hope you all stay busy. Over here, people just put family photos in the cluster in front of all those lights, I guess they figure "If I can't see that warning lamp, there is not a problem!"


    Cheers
    S. Breland

    Comment

    • Foden
      Junior Member
      • Mar 2011
      • 27

      #3
      no bad thing !

      in my own opinion as a sole trader and one man band and seeing a lot of ignored safety issues this is no bad thing not only is it good for business its better for the customer safety wise !
      i know we live in hard economic times at present but motor vehicles need to be kept at safe standards whatever the cost and if bringing in more items to the m.o.t test does that then fair one

      hope i dont get flamed for me opinion lol

      Comment

      • David Green
        Senior Member
        • Oct 2009
        • 382

        #4
        Some other things they have brought into the inspection as well, such as split dust covers on ball joints, all CV gaiters split etc.

        Did an examination today on a car the offside front lower suspension had just been fitted, brand new one and the ball joint dust cover was already split?

        Probably bad fiment that did it, but January on it's a fail

        Hope all these mechanics stop splitting them now

        David

        Comment

        • Crusty
          Senior Member
          • Dec 2007
          • 2450

          #5
          Originally posted by Foden
          in my own opinion as a sole trader and one man band and seeing a lot of ignored safety issues this is no bad thing not only is it good for business its better for the customer safety wise !
          i know we live in hard economic times at present but motor vehicles need to be kept at safe standards whatever the cost and if bringing in more items to the m.o.t test does that then fair one

          hope i dont get flamed for me opinion lol
          No flaming from this part of Ontario Canada-!!
          If someone wants to go plant themselves into a tree in the local forestry area, so be it.....that's their choice.....BUT....they have NO RIGHT to put others at risk on two lane blacktop.

          There is a responsibility that goes hand in hand with operating a motor vehicle on public roads.

          JMO

          Comment

          • David Green
            Senior Member
            • Oct 2009
            • 382

            #6
            Hi Foden,

            If you get any customers complaining about "power loss" with their vehicles, don't forget to "check" for "Turbo Lag" lol

            David

            Comment

            • Foden
              Junior Member
              • Mar 2011
              • 27

              #7
              he he

              no probs m8 ill remember that lol lol
              but i honestly dont know what yer reffering to lol i mean my avatar cant be it ? cos i put a pic of a hairdrier on there

              Comment

              • David Green
                Senior Member
                • Oct 2009
                • 382

                #8
                I did serve my time at Dewhurst LOL, I must be good if I can't even know the difference between a hairdryer and a turbo LOL

                Just imagine what will happen when they let me loose under the bonnet (Hood) over the pond

                Frightening stuff

                Comment

                • Crusty
                  Senior Member
                  • Dec 2007
                  • 2450

                  #9
                  Originally posted by David Green
                  I did serve my time at Dewhurst LOL, I must be good if I can't even know the difference between a hairdryer and a turbo LOL

                  Just imagine what will happen when they let me loose under the bonnet (Hood) over the pond

                  Frightening stuff
                  HECK, you guys "over the pond" cant spell TIRE right...LOL

                  And a "bonnett" is something girls put on their heads-!!!

                  Comment

                  • David Green
                    Senior Member
                    • Oct 2009
                    • 382

                    #10
                    Originally posted by Crusty
                    HECK, you guys "over the pond" cant spell TIRE right...LOL

                    And a "bonnett" is something girls put on their heads-!!!
                    OK then , we can however do this better than you

                    Find the braking torque on a leading brake shoe;

                    Applying a force of 600N, measure the radius of the drum, say 0.1m, and carry out an experiment to determine the coefficient of friction between the drum and the leading shoe, which results in a figure of 0.4.

                    Brake torque, TL = mewR {Wa / b - mewR}

                    = 0.4 x 0.1 {600 x 0.16 / 0.08 - (0.4 x 0.1) }

                    = 0.4 x 0.1 x 96 / 0.04 = 96 Nm

                    and if I wanted the trailing shoe torque;

                    = 0.4 x 0.1 { 600 x 0.16 / 0.08 + (0.4 x 0.1)}

                    = 0.4 x 0.1 x 96 / 0.12 = 32 Nm

                    Total brake torque developed = 128 Nm

                    Bet you can fix brakes better than me LOL

                    Comment

                    • USpMD
                      Senior Member
                      • Oct 2010
                      • 171

                      #11
                      Originally posted by David Green
                      OK then , we can however do this better than you

                      Find the braking torque on a leading brake shoe;

                      Applying a force of 600N, measure the radius of the drum, say 0.1m, and carry out an experiment to determine the coefficient of friction between the drum and the leading shoe, which results in a figure of 0.4.

                      Brake torque, TL = mewR {Wa / b - mewR}

                      = 0.4 x 0.1 {600 x 0.16 / 0.08 - (0.4 x 0.1) }

                      = 0.4 x 0.1 x 96 / 0.04 = 96 Nm

                      and if I wanted the trailing shoe torque;

                      = 0.4 x 0.1 { 600 x 0.16 / 0.08 + (0.4 x 0.1)}

                      = 0.4 x 0.1 x 96 / 0.12 = 32 Nm

                      Total brake torque developed = 128 Nm

                      Bet you can fix brakes better than me LOL
                      Bloody Hell!! Drum, Shoe, you guys overthere still working on carraiges?? step up mate, get yourself some discs and pads, they work much better, and you will no longer have to figure the coieficent of friction on either of the rear shoes
                      Last edited by USpMD; 09-25-2011, 06:18 PM.
                      "I wanna help the helpless, but I could careless about the clueless". Dennis Miller

                      Comment

                      • Crusty
                        Senior Member
                        • Dec 2007
                        • 2450

                        #12
                        Originally posted by David Green
                        OK then , we can however do this better than you

                        Find the braking torque on a leading brake shoe;

                        Applying a force of 600N, measure the radius of the drum, say 0.1m, and carry out an experiment to determine the coefficient of friction between the drum and the leading shoe, which results in a figure of 0.4.

                        Brake torque, TL = mewR {Wa / b - mewR}

                        = 0.4 x 0.1 {600 x 0.16 / 0.08 - (0.4 x 0.1) }

                        = 0.4 x 0.1 x 96 / 0.04 = 96 Nm

                        and if I wanted the trailing shoe torque;

                        = 0.4 x 0.1 { 600 x 0.16 / 0.08 + (0.4 x 0.1)}

                        = 0.4 x 0.1 x 96 / 0.12 = 32 Nm

                        Total brake torque developed = 128 Nm

                        Bet you can fix brakes better than me LOL
                        Do these drum brakes have a fixed lower anchor pin or are they "self-actuating"??

                        Heck I just throw the block of granite out the back and hope the natural fibre rope doesn't break-!!

                        Comment

                        • USpMD
                          Senior Member
                          • Oct 2010
                          • 171

                          #13
                          Are you guys still trying to work up a new question on drum brakes? Get over it, what else is up over the pond??
                          "I wanna help the helpless, but I could careless about the clueless". Dennis Miller

                          Comment

                          • USpMD
                            Senior Member
                            • Oct 2010
                            • 171

                            #14
                            Lets work together to solve our nightmares.....
                            "I wanna help the helpless, but I could careless about the clueless". Dennis Miller

                            Comment

                            • David Green
                              Senior Member
                              • Oct 2009
                              • 382

                              #15
                              Yep unfortunately we do still have drum brakes on the rear of some of our vehicles over the pond , but we also have disc brakes

                              I look at it like this;

                              Total force acting = hydraulic pressure x contact area of pad(s)

                              The frictional force acting as measured = 0.3

                              The frictional torque acting on the disc, frictional force x effective radius

                              so the contact area of each pad, A = pie/4 x 0.05^2 m^2

                              The measured hydraulic pressure, P = 490 x 10^3 N/m^2

                              The measured radius, R = 0.15m

                              Number of pad(s) 4

                              rotational speed of the disc, N = 500 rev/min in this example.

                              = 0.3 x 490 x 10^3 x pie x (0.05)^2 x 4 x 0.15 / 4 = 173 N/m

                              So the frictional torque = 173 N/m

                              That's a disc brake lol

                              I could go on to talk about proper brakes but you might not be ready for that yet over the pond

                              Comment

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